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The turntable of a record player rotates initially at 33 rev/min and takes 19 s to come to rest.?

February 27th, 2010 by admin

The turntable of a record player rotates initially at 33 rev/min and takes 19 s to come to rest.

(a) What is the angular acceleration of the turntable, assuming it is uniform?
__ rad/s2
(b) How many rotations does the turntable make before coming to rest?
__ rev
(c) If the radius of the turntable is 0.14 m, what is the initial linear speed of a bug riding on the rim?
__m/s
the first answer is still wrong

a) v = u + at
0 = 33*2pi/60 + 19a
19a = -66pi/60
19a = -1.1pi
a = -1.1pi/19
a = 0.18 red / s^2

b) s = (u + v)t / 2
s = (33/60 + 0)*19 / 2
s = 0.55 *19/2
s = 5.225 rev

c) 33/60 * 2*pi*0.14 = 0.55 * 0.28pi = 0.48 m/s

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One Response to “The turntable of a record player rotates initially at 33 rev/min and takes 19 s to come to rest.?”

  1. #1
    lavalamp3773
    February 27th, 2010 3:08 pm

    a) v = u + at
    0 = 33*2pi/60 + 19a
    19a = -66pi/60
    19a = -1.1pi
    a = -1.1pi/19
    a = 0.18 red / s^2

    b) s = (u + v)t / 2
    s = (33/60 + 0)*19 / 2
    s = 0.55 *19/2
    s = 5.225 rev

    c) 33/60 * 2*pi*0.14 = 0.55 * 0.28pi = 0.48 m/s
    References :

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